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November 24, 2014

November 24, 2014

Posted by **Alison** on Wednesday, November 30, 2011 at 4:17am.

Find the second-degree Taylor polynomial for f(x)=4x2−7x+6 about x=0

thank you! (:

- math (taylor polynomials) -
**MathMate**, Thursday, December 1, 2011 at 6:54amTaylor's series about a (to x² term):

f(x)=f(a) + f'(a)x/1! + f"(a)x²/2!

For

f(x)=(4/3)(7x+50)=(28x/3)+200/3, and a=2

f'(x)=28/3

f"(x)=0

f(x)=f(2) + f'(2)(x-2)/1! + f"(2)(x-2)²/2!

=(4/3)(64) + 28/3(x-2) + 0(x-2)²/2!

=(4/3)(7x-50)

Try the second one along the same lines, and post if you would like to check the answer, which should be the same as the original function.

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