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March 29, 2017

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Consider the reversible reaction: A(g)-2B(g)At equilibrium, the concentration of A is 0.381 M and that of B is 0.154 M. What is the value of the equilibrium constant, Keq?

  • Chemistry - ,

    A ==> 2B
    Kc = (B)^2/(A)
    Kc = (0.154)^2/(0.381)
    You do the math.

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