Questions LLC
Login
or
Sign Up
Ask a New Question
Science
Physics
it takes a maximum force of 460 N to move a 125 kg crate. What is the coefficient of the maximum static friction between the crate and the floor?
1 answer
weight = m g = 125*9.81
460 = mu * 125*9.81
solve for mu
You can
ask a new question
or
answer this question
.
Similar Questions
it takes a maximum force of 460 N to move a 125 kg crate. What is the coefficient of the maximum static friction between the
Top answer:
See your 7:56pm post for solution.
Read more.
it takes a maximum force of 460 N to move a 125 kg crate. What is the coefficient of the maximum static friction between the
Top answer:
Wc = mg = 125kg * 9.8N/kg = 1225N = Weight of crate. Fc = 1225N @ 0deg. Fp = 1225sin(0) = 0 = Force
Read more.
it takes a maximum force of 460 N to move a 125 kg crate. What is the coefficient of the maximum static friction between the
Top answer:
See your 7:56pm post for solution.
Read more.
A horizontal force of 45N applied to a crate of mass 9kg is just sufficient to move it. If the crate is now pulled at an angle
Top answer:
The answer is 43.86N
Read more.
To move a large crate across a rough floor, you push on it with a force F at an angle of 21¨¬ below the horizontal. The mass
Top answer:
x: Fcosα –F(fr) =0 y: N-mg-Fsinα = 0 => N= mg+Fsinα Fcosα =F(fr) =μ⒦•N = μ⒦•
Read more.
The man slides the 100-kg crate across force of 200 N. If the crate was initially at rest, how far will the crate move before
its
Top answer:
Well, it seems like the man is in quite a slippery situation, both literally and figuratively!
Read more.
To move a large crate across a rough floor, you push on it with a force F at an angle of 21° below the horizontal, as shown in
Top answer:
To find the force necessary to start the crate moving, we need to consider the forces acting on the
Read more.
To move a large crate across a rough floor, you push on it with a force F at an angle of 21° below the horizontal, as shown in
Top answer:
I am not certain which way the force is directed: I assume downward. force normal=mg+F*sinTheta
Read more.
To move a large crate across a rough floor, you push on it with a force F at an angle of 21°, below the horizontal, as shown in
Top answer:
Use the same approach used here. Only the numbers have changed.
Read more.
To move a large crate across a rough floor, you push on it with a force (F) at an angle of 21 degrees below the horizontal. Find
Top answer:
To find the force necessary to start the crate moving, you need to consider the forces acting on the
Read more.
Related Questions
a crate is pushed to the top of a frictionless inclined plane 15 m long with a force of 25 N.
If the crate weighs 125 N, how high
An electric motor is rated to have a maximum power output of 0.72 hp. If this motor is being used to lift a crate of mass 188
A man pulls a crate of mass 53.0 kg across a level floor. He pulls with a force of 180.0 N at an angle of 28.0° above the
A 30 N crate is submerged in water. The amount of buoyant force acting on the crate is 25 N. What will the crate do?
The crate
The drawing shows a 25.1-kg crate that is initially at rest. Note that the view is one looking down on the top of the crate. Two
A force of F = 125 N is used to drag a crate 3.0 m across a floor. The force is directed at an angle upward from the crate so
A crate is pulled to the right with a force of 80 N, to the left with a force of 125.8 N, upward with a force of 615.4 N, and
drawing shows a 25.0-kg crate that is initially at rest. Note that the view is one looking down on the top of the crate. Two
A 46.6 kg crate is at rest on a level floor, and te coefficient of kinetic friction is 0.32. The acceleration of gravity is
a man applies a force of 220 N horizontally to the right against a 50 kg crate. the force of friction between the crate and the
