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November 28, 2014

November 28, 2014

Posted by **Allison Anderson** on Tuesday, November 29, 2011 at 5:28pm.

nature of the solutions. -9x^2+6x-2=0 what is the value of the discriminant? Which one

of the statements below is correct? A) the equation has two imaginary solutions. B) the

equation has two real solutions. C) the equation has one real solution

I have this has two real solutions and the discriminant is 49

Is this correct?

- Math -
**Reiny**, Tuesday, November 29, 2011 at 5:50pmThere is no need for an equation to ever start with a negative term, we can just multiply each term by -1 (just switch the signs)

-9x^2 + 6x - 2 = 0

9x^2 - 6x + 2 = 0

discr. = b^2 - 4ac = 36 - 4(9)(2) = -36

so there are two imaginary solutions.

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