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trig

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For the following expression, find the value of y that corresponds to each value of x, then write your results as ordered pairs (x,y).
y=7cos(x-pi/6) for x=pi/6, pi/3, 2pi/3, pi, 7pi/6

  • trig - ,

    I will do the first one, you do the others.
    Let me know what you get.

    y = 7cos(x-π/6) , for x = π/6
    = 7cos(π/6 - π/6)
    = 7cos 0
    = 7(1) = 7

    one more... if x = 2π/3
    y = 7cos(2π/3 - π/6)
    = 7cos (π/2)
    = 7(0) = 0

  • trig - ,

    i didn't realize it was just plugging in! thanks! i just need to figure out how to subtract fractions with pi in them now

  • trig - ,

    pi/3 is 7 square root 3/ 2 pi is - 7 square root 3 / 2 and 7pi/6 is -7

  • trig - ,

    I don't like the way you wrote those answers

    Be mathematically correct, ..... e.g.

    if x = π/3
    y = 7cos(π/3 - π/6)
    = 7 cos (π/6)
    = 7(√3/2) = 7√3/2

    if x = 7π/6
    y = 7cos(7π/6 - π/6)
    = 7cos π
    = 7(-1) = -7

    A statement such as "π/3 is 7√3/2" makes no sense

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