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December 20, 2014

December 20, 2014

Posted by **Lindsey** on Tuesday, November 29, 2011 at 4:58pm.

ln|cot x| = ln|cos x| - ln|sin x|

I have no idea where to begin with this one... your help is appreciated!

- Trigonometry -
**Reiny**, Tuesday, November 29, 2011 at 5:02pmRS = ln (|cosx|/|sinx|)

= ln |cot x|

= LS

using cot Ų = cosŲ/sinŲ

and

log A - logB = log(A/B)

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