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October 1, 2014

October 1, 2014

Posted by **Alison** on Tuesday, November 29, 2011 at 4:06pm.

Round your answers to the nearest thousandth

Cheers in advance!

- Math (linear approximation) -
**Steve**, Tuesday, November 29, 2011 at 4:47pmAny curve can be approximated by a straight line, in a small enough interval. So, we want the tangent line at x=0, which will be very close to the curve, if we stay close enough to x=0.

y=(1+x)^(1/4)

y(0) = 1

y' = 1/4 * (1+x)^(-3/4)

= 1/[4(1+x)^3]

y'(0) = 1/4

So, the line y = x/4 + 1 is tangent to f(x) at x=0

let x = -0.05

y = -.0125 + 1 = 0.9875

If x = .1

y = .025 + 1 = 1.025

Just to check,

.95^(1/4) = 0.9873

1.1^(1/4) = 1.0241

Since |.95 - 1| < |1.1 - 1| the approximation is better

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