this is a math riddle that i can't do so please help i am a fraction eguivalent to 2/4 the sum of my numerator and my denominator is 21 what fraction am i

here it is help me please's

Since the sum is odd, either the numerator or denominator is odd.

Since the fraction is 1/2, the denominator is even. So, we want a faction with odd numerator, even denominator, where they add to 21 and denominator is twice the numerator.

1/2? no
3/6? no
5/10? no
7/14 <<<---

or, since the denominator is twice the numerator, that means 3 times the numerator is 21. So, 7/14.

To solve this math riddle, let's break it down step by step.

Step 1: Identify the fraction equivalent to 2/4.
Since 2 is half of 4, the fraction equivalent to 2/4 is 1/2.

Step 2: Find a fraction where the sum of the numerator and denominator is 21.
Let's express the fraction as x/y, where x is the numerator and y is the denominator. The condition given tells us that x + y = 21.

Step 3: Substitute the value of x in terms of y.
Since we already know the equivalent fraction is 1/2, x = 1. Therefore, we have 1 + y = 21.

Step 4: Solve for y.
To isolate y, we subtract 1 from both sides of the equation:
1 + y - 1 = 21 - 1
y = 20

Step 5: Determine the fraction.
Now that we know the value of y is 20, we can conclude that the fraction is 1/20.

So, the fraction you are looking for is 1/20.