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Posted by on Tuesday, November 29, 2011 at 1:49pm.

__X+1____-__x-1____
x-1 x+1

  • math - , Tuesday, November 29, 2011 at 2:26pm

    If that means

    (x+1)/(x-1) - (x-1)/(x+1) then we have

    [(x+1)^2 - (x-1)^2]/(x^2-1)
    = [(x^2 + 2x + 1 - (x^2 - 2x + 1)]/(x^2-1)
    = 4x/(x^2-1)

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