roger took off at 8am driving 45mph. bill went after him 2 hours later and caught up with him at 4pm. how fast did bill drive?

the distances must be the same, so if Bill's velocity = v,

8*45 = 6*v
v = 60

8 times 45 =360 how did you get 60

because 360 = 6v

d1 = d2 = VT = 45 * 8 = 360 Miles.

d2 = VT,
V = d2/T = 360 / (8-2) = 60mi/h.

To find out how fast Bill drove, we can start by calculating the time it took for him to catch up with Roger. We know that Roger started driving at 8am and Bill started driving 2 hours later. Therefore, the total time elapsed when Bill caught up with Roger is 4pm - 8am = 8 hours.

Since we know that Roger was driving at a constant speed of 45 mph, we can calculate the distance traveled by him during these 8 hours: Distance = Speed × Time = 45 mph × 8 hours = 360 miles.

Since Bill caught up with Roger, we can assume that he covered the same distance, 360 miles. To find out how fast Bill drove, we can divide the distance by the time it took to cover it: Speed = Distance ÷ Time = 360 miles ÷ 8 hours = 45 mph.

Therefore, the speed at which Bill drove is also 45 mph, just like Roger.