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Math(module 4 Calculus)

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(minimum commuting time) A lighthouse lies 2 miles offshore directly across from point A of a straight coastline. The lighthouse keeper lives 5 miles down the coast from point A.What is the minimum time it will take the lighthouse keeper to commute to work, rowing his boat at 3 miles per hour, and walking at 5 miles per hour?

  • Math(module 4 Calculus) - ,

    Let the distance from A to his landing place be x
    then from there it would be another 5-x miles to his house.
    let the distance he rows be d
    d^2 = x^2 + 2^2
    d = (x^2 + 4)^(1/2)

    time for the rowing part = (x^2 + 4)^(1/2) /3
    time for the walking part = (5-x)/5

    Time = (x^2 + 4)^(1/2) /3 + (5-x)/5
    d(Time)/dx = (1/6)(x^2 + 4)^(-1/2) (2x) - 1/5
    x/(3√(x^2+4) ) - 1/5
    = 0 for a minimum of Time.

    x/(3√(x^2+4) ) - 1/5
    5x = 3√(x^2 + 4)
    25x^2 = 9(x^2+4)
    25x^2 = 9x^2 + 36
    16x^2 = 36
    4x = 6
    x = 6/4

    sub that into Time = .. and you got it
    ( I got 1 hour and 32 minutes)
    check my arithmetic

  • Math(module 4 Calculus) - ,

    yoo

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