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Posted by on Tuesday, November 29, 2011 at 2:36am.

Find the area under the curve y=5(cosx) and above y=5(sinx) for 0<x<pi

  • Calculus - , Tuesday, November 29, 2011 at 6:01am

    Sketch a graph of the two functions between 0 and pi.
    Note that cos x is above sin x only between x = 0 and x = pi/4
    so
    we have 5 times integral from 0 to pi/4 of cos x dx - sin x dx
    cos x dx --> sin x 0 to pi/4 = .5 sqrt 2
    sin x dx = -cos x 0 to pi/4= -.5sqrt 2 +1
    cos x dx - sin x dx --> sqrt 2 - 1
    times 5 = 5 sqrt 2 - 5
    or about 7.07 - 5 = 2.07

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