Posted by ... on Tuesday, November 29, 2011 at 12:40am.
3.5/2 = 1.75 seconds to peak height
v = Vi - g t
0 = 13.6 - g (1.75) solve for local g on surface. At 2 r it is g/4
340 min = 340 * 60 seconds = T
m * centripetal acceleration = m (g/4) at 2 radii from center
m v^2/2r = = m g/4
v^2/r = g/2
but we know T
v T = 2 pi (2r) = 4 pi r
v = 4 pi r/T
v^2 = 16 pi^2 r^2/T^2
v^2/r = (16 pi^2/T^2) r
so in the end
r = (g/2)/(16 pi^2/T^2)
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