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April 18, 2015

Posted by **...** on Tuesday, November 29, 2011 at 12:40am.

What is the mass (in kg) of the planet?

- Physics help please! -
**Damon**, Tuesday, November 29, 2011 at 6:16am3.5/2 = 1.75 seconds to peak height

v = Vi - g t

0 = 13.6 - g (1.75) solve for local g on surface. At 2 r it is g/4

340 min = 340 * 60 seconds = T

m * centripetal acceleration = m (g/4) at 2 radii from center

m v^2/2r = = m g/4

v^2/r = g/2

but we know T

v T = 2 pi (2r) = 4 pi r

v = 4 pi r/T

v^2 = 16 pi^2 r^2/T^2

v^2/r = (16 pi^2/T^2) r

so in the end

r = (g/2)/(16 pi^2/T^2)

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