YW bisects angle XYZ. m of angle XYW = (2x + 7)degrees and m of angle XYZ = (6x - 8)degrees. Find the value of 'x'.
Triangle xyz has angles measure in the ratio 3:4:5 what is the measure of the largest angle?
To find the value of 'x', we can use the fact that YW bisects angle XYZ. This means that angle XYW and angle YWZ are congruent (or equal in measure).
Given that the measure of angle XYW is (2x + 7) degrees and the measure of angle XYZ is (6x - 8) degrees, we can set up an equation:
2x + 7 = 6x - 8
Next, we can solve this equation to find the value of 'x':
2x + 7 - 2x = 6x - 8 - 2x
7 = 4x - 8
We want to isolate 'x', so let's add 8 to both sides of the equation:
7 + 8 = 4x - 8 + 8
15 = 4x
Finally, divide both sides by 4 to solve for 'x':
15/4 = 4x/4
3.75 = x
Therefore, the value of 'x' is 3.75.
Since the angle is bisected,
2(2x+7) = 6x-8
4x + 14 = 6x - 8
2x = 22
x = 11
m<XYZ = 58
m<XYW = 29
you did your math wrong
-2x=6
x=-3