If the dummy is thrown forward with a force of 130.0 n while simultaneously being hit from side with a force of 4500.0n what force will the seat belt have exert on the dummy to hold in seat
Well, it seems like the dummy is having quite a colorful experience! Now, let's calculate the force exerted by the seat belt to keep the dummy in the seat.
To solve this, we need to break down the forces acting on the dummy. We have a forward force of 130.0 N and a side force of 4500.0 N. Since these forces are acting simultaneously, we can't simply add them up.
Since the forces are perpendicular, we can use the Pythagorean theorem to find the resultant force:
Resultant force = √(130.0^2 + 4500.0^2) = √(16900 + 20250000) = √20266900 ≈ 4509.0 N
So, the force exerted by the seat belt to hold the dummy in the seat would be approximately 4509.0 N. That's quite a hefty force! I hope that seat belt is up for the task!
To determine the net force experienced by the dummy, we need to calculate the vector sum of the forces acting on it.
Given:
Force forward (from throwing): 130.0 N
Force from the side: 4500.0 N
Let's assume the force exerted by the seat belt is "F" (unknown).
Since the forces are acting in different directions, we need to find the resultant force.
Using vector addition, we have:
Resultant force = √(Force forward^2 + Force side^2)
Resultant force = √(130.0^2 + 4500.0^2)
Resultant force = √(16900.0 + 20250000.0)
Resultant force = √(20266900.0)
Resultant force ≈ 4504.3 N (rounded to one decimal place)
Since the seat belt is holding the dummy in the seat, the seat belt must exert a force equal to the resultant force.
Therefore, the force exerted by the seat belt on the dummy to hold it in the seat is approximately 4504.3 N.
To determine the force exerted by the seat belt on the dummy, we need to consider the combined effect of the forces acting on the dummy in both the forward and sideways directions.
First, let's break down the forces acting on the dummy:
1. The forward force of 130.0 N: This force represents the dummy being thrown forward. It acts in the forward direction.
2. The sideways force of 4500.0 N: This force represents the dummy being hit from the side. It acts in the sideways direction.
Since these forces are acting in different directions, we need to use vector addition to find the resultant force. We can use the Pythagorean theorem to find the magnitude of this resultant force, and the trigonometric functions to determine its direction.
Using the Pythagorean theorem:
Magnitude of resultant force = sqrt((130.0N)^2 + (4500.0N)^2)
= sqrt(16900N^2 + 20250000N^2)
= sqrt(2035900N^2)
≈ 1427.74 N
Next, we can use trigonometry to find the direction of the resultant force:
Angle θ = arctan(opposite/adjacent) = arctan(4500.0N / 130.0N) ≈ 86.6°
Now that we have the magnitude and direction of the resultant force, we can determine the force exerted by the seat belt on the dummy.
Since the seat belt's primary purpose is to restrain the dummy and keep it in the seat, it will exert a force in the opposite direction of the resultant force.
Therefore, the force exerted by the seat belt on the dummy is approximately 1427.74 N, but in the opposite direction (86.6° away from the forward direction).