Posted by Leah on Monday, November 28, 2011 at 10:30pm.
A person pushes a 11.0 kg lawn mower at constant speed with a force of 76.0 N directed along the handle, which is at an angle of è = 41.0° to the horizontal. Calculate the normal force exerted vertically upward on the mower by the ground. Calculate the force the person must exert on the lawn mower to accelerate it from rest to 1.3 m/s in 2.0 seconds (assuming the same retarding force).

Physics  Henry, Wednesday, November 30, 2011 at 5:33pm
W = mg = 11kg * 9.8N/kg = 107.8N. =
Weight of lawn mower.
Fm = 107.8N @ 0deg. = Force of mower.
Fp = Fh = 107.8sin(0) = 0 = Force parallel to ground = Hor comp.
Fv = 107.8cos(0) = 107.8N. = Force perpendicular to ground.
a. Fn = Fv + Fap*sin41,
Fn = 107.8 + 76sin41 = 157.7N.=Normal force upward from ground.
b. a = (Vf  Vo) / t,
a = (1.3  0) / 2 = 0.65m/s^2.
Fap = 76 + ma = 76 + 11*0.65 = 83.15N.
= Force applied.
Answer This Question
Related Questions
 physics  A person pushes a 17.0 kg lawn mower at constant speed with a force of...
 physics  A person pushes a 14.0kg lawn mower at constant speed with a force of...
 physics  A person pushes a 11.0 kg lawn mower at constant speed with a force of...
 Ap physics  A person pushes a 15.0 kg lawn mower at constant speed with a force...
 physics  forces  A person pushes a 16.0 kg lawn mower at constant speed with a...
 physics  A person pushes a 10.0 kg lawn mower at constant speed with a force of...
 12th grade Physics  A boy pushes a lawn mower with a mas of 17.9 kg starting ...
 physics  A person pushes a 14.5 kg lawnmower at constant speed with a force of ...
 11th grade physics  Rachel pulls her 177N suitcase at a constant speed by ...
 Physics  A student pushes stright along the handles of a mower with a force of ...
More Related Questions