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March 27, 2017

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Show that the given line integral is independent of path.Then, evaluate the line integral I by finding a potential function f and applying the Fundamental Theorem of Line Integrals. I=ç_{(0,0)}^{(1,2)}(x+y)dx+(x-y)dy

  • vector calculus - ,

    If F is a conservative field, then there will be a G such that F = ∇G.

    If we let G(x,y) = 1/2 (x^2 + 2xy - y^2) then
    ∇G = 1/2 (2x dx + 2y dx + 2x dy - 2y dy)
    = (x+y)dx + (x-y)dy


    So, F is a conservative field and the line integral is path-independent.

    So, just evaluate G at the limits of integration

    G(1,2) = 1/2 (1+4-4) = 1/2
    G(0,0) = 0

    So, the integral evaluates to just 1/2

    If I recall my vector calculus correctly...

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