Posted by Donny on Monday, November 28, 2011 at 9:26pm.
If F is a conservative field, then there will be a G such that F = ∇G.
If we let G(x,y) = 1/2 (x^2 + 2xy - y^2) then
∇G = 1/2 (2x dx + 2y dx + 2x dy - 2y dy)
= (x+y)dx + (x-y)dy
So, F is a conservative field and the line integral is path-independent.
So, just evaluate G at the limits of integration
G(1,2) = 1/2 (1+4-4) = 1/2
G(0,0) = 0
So, the integral evaluates to just 1/2
If I recall my vector calculus correctly...
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