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April 20, 2014

April 20, 2014

Posted by **ekaterina** on Monday, November 28, 2011 at 6:12pm.

- physics -
**Damon**, Monday, November 28, 2011 at 6:32pmKinetic energy of jump = (1/2) m v^2

= (1/2)(68)(3.4)^2 = 393 Joules

.25(3500-2500) = 250 food calories to burn

1 food calorie (1000 physics heat calories) = 4184 Joules

250 Cal * 4184 J/Cal = 1,046,000 Joules

so

1,046,000/393 = 2661 Jumps

- Luckily saw whole problem before the 25% efficiency part was deleted -
**Damon**, Monday, November 28, 2011 at 6:34pmI was working on your final version.

- physics -
**Ms. Sue**, Monday, November 28, 2011 at 6:58pmSorry, Damon. I thought she'd posted exactly the same question a dozen times, so I deleted the extras.

- physics -
**Damon**, Monday, November 28, 2011 at 6:59pmLOL - does not matter. I had already copied the last one.

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