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November 20, 2014

November 20, 2014

Posted by **Julie** on Monday, November 28, 2011 at 1:44pm.

- Calculus AB/AP -
**Steve**, Monday, November 28, 2011 at 2:16pmIf we let the length be L and the height be H, then we have

4LH = 36

LH = 9

L = 9/H

The cost

C = 4L*8 + 4*4H*4

C = 32(9/H) + 64H

C = 288/H + 64H

dC/dH = 64 - 288/H^2

dC/dH = 0 when H = √2.5 = 2.12

so L = 4.24

C = 288/2.12 + 64*2.12 = $271.53

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