Saturday

February 28, 2015

February 28, 2015

Posted by **jan** on Monday, November 28, 2011 at 11:51am.

- precalculus -
**Steve**, Monday, November 28, 2011 at 12:56pmJust take this one step at a time:

a line with inclination 30° has slope tan30° = 1/√3

Now we have a point and a slope, so that line is

(y+7)/(x-1) = 1/√3

y = 1/√3 x - (7+1/√3)

Now find where that line intersects the parabola:

2x^2 - 6x - 3 = 1/√3 x - (7 + 1/√3)

x = 1

x = 2 + 1/(2√3) or 2.288

The second point of intersection is thus

(2 + 1/(2√3) , 1/(2√3) - 41/6)

or (2.288,-6.256)

**Answer this Question**

**Related Questions**

Calculus - Sketch a graph of the parabola y=x^2+3. On the same graph, plot the ...

Parabola Help - by plotting the graph of parabola y=2+3x-2x^2 which 3 option are...

math - A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) ...

math - A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) ...

Calculus - Find expressions for the quadratic functions whose graphs are shown. ...

College Algebra - Find the equation of the parabola y = ax2 + bx + c that passes...

Math - If f(x)=3x^2-5x, find the f'(2) & use it to find an equation of tangent ...

Algebra 1 parabola's - I have a graph with a parabola on it and asked to write ...

Algebra: Parabolas - I have a math problem that requires me to find the focal ...

Exploring Quadratic Graphs - ok, I totally did not get this question at all. ...