Posted by **jan** on Monday, November 28, 2011 at 11:51am.

graph the parabola y=2x^2-6x-3. plot point on the parabola A[1,-7] and draw a line through A with an angle of inclination equal to 30 degrees. then find the equation of the line and its second point of intersection B, with the parabola

- precalculus -
**Steve**, Monday, November 28, 2011 at 12:56pm
Just take this one step at a time:

a line with inclination 30° has slope tan30° = 1/√3

Now we have a point and a slope, so that line is

(y+7)/(x-1) = 1/√3

y = 1/√3 x - (7+1/√3)

Now find where that line intersects the parabola:

2x^2 - 6x - 3 = 1/√3 x - (7 + 1/√3)

x = 1

x = 2 + 1/(2√3) or 2.288

The second point of intersection is thus

(2 + 1/(2√3) , 1/(2√3) - 41/6)

or (2.288,-6.256)

## Answer this Question

## Related Questions

- Calculus - Sketch a graph of the parabola y=x^2+3. On the same graph, plot the ...
- Algebra... - Write the equation of a vertical line passing through the point (8...
- Parabola Help - by plotting the graph of parabola y=2+3x-2x^2 which 3 option are...
- Calc. - Find the area of the region bounded by the parabola y=x^2, the tangent ...
- math - A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) ...
- Physics - A car acclerates at 4m/s/s for 5s and then drove at its final velocity...
- Math - If f(x)=3x^2-5x, find the f'(2) & use it to find an equation of tangent ...
- math - A parabola has the equation y = 4(x-3)^2-7 Choose 2 true statements: A) ...
- maths - consider the line y=6x-k and the parabola y=x^2 i) for what value of k ...
- calculus - A point in the first quadrant lies on the parabola y = x^2. Express ...