posted by Yuli on .
A cable lifts a 1220-kg elevator at a constant velocity for a distance of 39.7 m. What is the work done by the tension in the cable?
can someone help me with this the answer is supposed to be in joules i tried doing it by 1220(9.81)(39.7) = 475137J but that is not the answer can someone please explain it to me?
475,137.54 or 475,138
475,000 J to three significant figures