Monday

September 22, 2014

September 22, 2014

Posted by **carlton** on Sunday, November 27, 2011 at 10:28pm.

At the same time, the vector position of a 5.20 g particle varies according to the following equation.

For each equation, t is in s and r is in cm. Solve the following when t = 2.00

(a) Find the vector position of the center of mass.

cm

cm

(b) Find the linear momentum of the system.

g-cm/s

g-cm/s

(c) Find the velocity of the center of mass.

cm/s

cm/s

(d) Find the acceleration of the center of mass.

cm/s2

cm/s2

(e) Find the net force exerted on the two-particle system.

μN

μN

- physics -
**Henry**, Monday, November 28, 2011 at 9:05pmWhere is the "following Eq"?

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