Posted by rachel on Sunday, November 27, 2011 at 6:00pm.
My applied calculus is a little rusty but I think I figured it out.
let x=# of people over 50 that attend
your revenue function would be:
(50+x)(200-2x)
10000+100x-2x^2
Cost function:
6000+32(50+x)
7600+32x
Profit function (subtract the two):
Yp=(-2x^2+100x+10000)-(7600+32x)
simplify
Yp=-2x^2+68x+2400
Take derivative
y'=-4x+68
Set equal to zero and solve
0=-4x+68
4x=68
x=17
But remember we let x equal to number of attendees over 50, so we have to add it to get our total number of people
67 people will maximize your profit
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