To determine the question use Frogs F and G are 5cm to cube and 40cm to cube.
a. Ratio
What are ratio volumes and surface areas for a frog? (The formula for figuring out this data A correlation V square=2/3
Ratio Volumes: Surface areas:
b. Toxin
Let us say that Frog F absorbs 0.015 mL of a certain toxin, then how much would Frog G absorb? mL.
c. Concentration
In order to figure out concentration of a toxin amount for the frog we would divide by the volume. What would the concentration be for frog F and frog G.
Concentration
Frog F:
Frog G:
a. To determine the ratio of volumes and surface areas for the frogs, we need to use the formula A/V^(2/3), where A represents the surface area and V represents the volume of the frogs.
For Frog F, given that its volume is 5 cm^3, we can calculate its surface area. Using the formula, the surface area for Frog F would be A = (5 cm^3)^(2/3) = 2.924 cm^2 (approximately).
For Frog G, given that its volume is 40 cm^3, we can calculate its surface area. Using the formula, the surface area for Frog G would be A = (40 cm^3)^(2/3) = 17.788 cm^2 (approximately).
Therefore, the ratio of volumes for the frogs would be 5:40, which can be simplified to 1:8. Additionally, the ratio of surface areas for the frogs would be approximately 2.924:17.788, which can be simplified to approximately 1:6.
b. If Frog F absorbs 0.015 mL of a certain toxin, to determine how much Frog G would absorb, we need to compare the volumes of the two frogs.
Given that Frog F has a volume of 5 cm^3 and Frog G has a volume of 40 cm^3, we can set up a proportion:
Volume of Frog F / Volume of Frog G = Amount absorbed by Frog F / Amount absorbed by Frog G
5 cm^3 / 40 cm^3 = 0.015 mL / x mL
To find x, we can cross-multiply and solve for x:
5 cm^3 * x mL = 40 cm^3 * 0.015 mL
x = (40 cm^3 * 0.015 mL) / 5 cm^3
x = 0.12 mL
Therefore, Frog G would absorb 0.12 mL of the certain toxin.
c. To find the concentration of the toxin for Frog F and Frog G, we divide the amount absorbed by the respective volume of the frog.
For Frog F, given that it absorbed 0.015 mL of the toxin and has a volume of 5 cm^3, the concentration would be:
Concentration for Frog F = Amount absorbed / Volume of Frog F
= 0.015 mL / 5 cm^3
= 0.003 mL/cm^3
For Frog G, given that it absorbed 0.12 mL of the toxin and has a volume of 40 cm^3, the concentration would be:
Concentration for Frog G = Amount absorbed / Volume of Frog G
= 0.12 mL / 40 cm^3
= 0.003 mL/cm^3
Therefore, the concentration of the toxin for both Frog F and Frog G would be 0.003 mL/cm^3.