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July 28, 2014

July 28, 2014

Posted by **Marni** on Sunday, November 27, 2011 at 1:42pm.

- trig -
**bobpursley**, Sunday, November 27, 2011 at 1:51pmdraw the triangle: adjacent+.7, hypo, 1.0, opposite -.51

Tant=.51/.70, sint=-.51/1.0, and so on.

are you meant t is negative?

- trig -
**Reiny**, Sunday, November 27, 2011 at 2:06pmcost >0 and tant< 0 , then t is in IV

if cos t = .7 = 7/10, then my triangle is 7 - √51 - 10

sint = -√51/10 , csc t = -10/√51

cos t = 7/10, sec t = 10/7

tan t = -V51/7 , cot t = -7/√51

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