Use the Law of Sines to solve each triangle.

P=110 degrees p=125, r=200 in triangel PQR

p/sinP = r/sinR

125/sin 110 = 200/sinR
133.02 = 200/sinR
sinR = 1.50

eh? sine is always less than 1.
And, since P = 110 degrees, the other angles must be less than 70 degrees.

Since p is opposite the largest angle, it must be the longest side. How then can r be 200?

Better check your problem for typos.