Posted by Anon14 on Saturday, November 26, 2011 at 10:39pm.
Your swimming pool is square and 5.7 m on a side. It is 1.5 m deep in the morning. If the temperature changes by 14°C during the afternoon, how much does the depth of the water increase?

Physics  Temp and heat  drwls, Sunday, November 27, 2011 at 12:05am
5.7^2 * 1.5 m^3 is the volume in the morning, Vo.
In the afternoon, the volume increases by a factor V/Vo = K*delta T
where K is the bulk thermal expansion coefficient of water. You will need to look that up. DeltaT = 14 C
You will find that K depends upon temperature. To treat is as a constant, you need some idea of the average termperature. At about 20 C average temperature, K = 2*10^4
The pool depth will increase by the same ratio V/Vo, since the horizontal area will not change. Use that fact to deduce the depth change.
I get about 4 millimeters depth increase. Evaporation has been neglected.
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