A radioactive sample contains 2.45g of an isotope wiht a half life of 3.8 days. How much of the isotope in grams remains after 11.4 days?

please explain

k = 0.693/t1/2

Solve for t1/2 and substitute into the equation below.
ln(No/N) = kt
No = starting grams = 2.45 g
N = ending amount. Solve for this.
k = from above calculation.
t = 11.5 days.

0.30625

100g of radioactive mass has a half life of 5days.calculate the mass decayed off aafter 15days

To calculate the amount of the isotope that remains after 11.4 days, we need to use the concept of half-life.

Here's how you can solve this problem:

1. Determine the number of half-lives that have passed during the given time period.
- The half-life of the isotope is 3.8 days.
- Divide the given time period (11.4 days) by the half-life to find the number of half-lives:
11.4 days / 3.8 days = 3 half-lives

2. Calculate the remaining fraction of the isotope.
- Each half-life reduces the amount of the isotope to half of its previous value.
- After each half-life, the remaining fraction of the isotope is 1/2 of its previous value.
- Since we have 3 half-lives, the remaining fraction would be (1/2) * (1/2) * (1/2) = 1/8.

3. Calculate the remaining mass of the isotope.
- Multiply the initial mass (2.45g) by the remaining fraction (1/8) to find the remaining mass:
Remaining mass = 2.45g * (1/8) = 0.30625g

Therefore, after 11.4 days, there will be approximately 0.30625 grams of the isotope remaining.

100g of radioactive mass has a half life of 5days.calculate the mass decayed off aaftGood day sir, My Name is Oyindamola from Enterprise ware Technologies(Mr Seun Aina-Scott’s Company)

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