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July 22, 2014

July 22, 2014

Posted by **crystal** on Saturday, November 26, 2011 at 4:01am.

- calc -
**drwls**, Saturday, November 26, 2011 at 4:56amdV/dt = d/dt[(pi/3)*R^2*H]

= 30 ft^3/min

= (pi/3)(1/4)*d/dt[H^3] since H= 2R

dV/dt = 30 = (pi/4)*3H^2*dH/dt

Solve for dH/dt when H = 18

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