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September 30, 2014

September 30, 2014

Posted by **biniya** on Saturday, November 26, 2011 at 12:23am.

- science -
**drwls**, Saturday, November 26, 2011 at 1:11amI do not understand what you mean by a "frame". If is is "the same particle" in both "frames", why is the time dependence of the position vector different?

If you are talking about two different particles following different trajectories, then the problem makes sense. Just take the time derivative of the r' - r vector.

- physics -
**biniya**, Saturday, November 26, 2011 at 6:52amposition of a particle in frame s is given by r=(6t^2-4t)i-3t^3j+3k.in another frame s',its position of the same particle is given by r'=(6t^2+2t)i-(3t^3+8t)j+3k.what is the magnitude of relative velocity of s' with respect to s if r and r'are measured in metre and t in second.

- science -
**drwls**, Saturday, November 26, 2011 at 12:00pmI know the question, which you have merely repeated. You have not responded to my comments and suggestions

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