Calculus
posted by Heather .
Consider the illustration, which shows a rotating beam of light located 0.5 mile from a shoreline. The beam rotates at a rate of 4 revolutions per minute. How fast (in miles per minute) is the distance between the beam and the point where it strikes the shore changing at the instant when x = .25 miles?

It depends upon the angle that the shore makes with the beam.
What is x ?
An illustration is needed for me to make sense of this question. 
I recall seeing this type of question before, and I will assume it is the standard type.
Usually we are to find the speed of the light as it moves along the shore.
Draw a perpendicular line from the lighthouse to the shore.
Let the angle between the line to the shore and the beam of light be Ø , and let the light rotate counterclockwise.
dØ/dt = 4 (2π) radians/minute = 8π rad/min
Let the beam of light be x miles along the shore
tanØ = x/.5
x = .5tanØ
dx/dt = .5 sec^2 Ø dØ/dt
when x = .25
tanØ = .25/.5 = 1/2
cosØ = 2/√5
secØ = √5/2
sec^2 Ø = 5/4
dx = .5(5/4)(8π) miles/min = 5π miles/minute