Posted by Allison A on Thursday, November 24, 2011 at 9:38pm.
find the veretx, the line of symmetry, and the maximuym or minimum value of
f(x)=(x8)^22
Help

math  Steve, Friday, November 25, 2011 at 12:14am
Look at the function.
(x8)^2 is always positive. Its least value is where x=8, when it is zero.
However, you have (x8)^2, so it has a maximum value at x = 8.
So, the vertex is obviously where x=8. That means that the vertex is (8,f(8)) = (8,2)
The yvalue at the vertex is the maximum or minimum value.
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