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December 20, 2014

December 20, 2014

Posted by **-Untamed-** on Thursday, November 24, 2011 at 9:22pm.

describe how the graphs of the following functions relate to the graph of y=x^2.

Could someone please tell me what that means? I sort of understand it, but I want to get it perfectly straight.

y = (x+5)^2

Since it's in the brackets, that would mean go five units horizontally. And would it go negative because doesn't it go in the opposite direction?:S

y = x^2-7. Is -7 the slope?

y = 5+(x-2)^2. This one is confusing.

- Math -
**Steve**, Friday, November 25, 2011 at 12:09amYou are correct on the first one. The new function is x^2 if we use a value 5 less than originally. That is, the graph is shifted 5 units to the left.

y = x^2 - 7

is just the graph of y=x^2, but shifted down 7 units.

Now you come upon shifting in both directions.

shift 2 units right, then 5 units up.

In general, the graph of y = f(x) is shifted h units to the right and k units up if

(y-k) = f(x-h)

You can see that the new function is just f(x) if we adjust the values of x and y by h and k, respectively.

- Math -
**Steve**, Friday, November 25, 2011 at 12:11amIf you want to play around with graphs, go to

rechneronline dot de slash function-graphs

You can type in a function f(x) of your choosing (they start out showing x^2). Then, just substitute (x-2) for x and see how the graph shifts.

It's also cool because you can show both graphs at once, in different colors.

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