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March 4, 2015

March 4, 2015

Posted by **kmoore** on Thursday, November 24, 2011 at 7:19pm.

9(b to the 4th power) - 200

- advanced algebra -
**Steve**, Thursday, November 24, 2011 at 7:34pm9b^4 - 200

= (3b^2 - √200)(3b^2 + √200)

= (√3b - √√200)(√3b + √√200)(3b^2 + √200)

where √√200 means the 4th root.

Not sure how far you want to go with this. We could also factor using complex numbers:

= (√3b - √√200)(√3b + √√200)(√3b - i√√200)(√3b + i√√200)

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