Posted by **maria** on Thursday, November 24, 2011 at 8:30am.

Tina randomly selects two distinct

numbers from the set {1, 2, 3, 4, 5}, and

Sergio randomly selects a number from the set {1, 2, . . . , 10}. The probability that Sergios number is larger than the sum of the two numbers chosen by Tina is ?

- Probability PLEASE HELP -
**Reiny**, Thursday, November 24, 2011 at 9:03am
the number of pairs that Tina could choose is C(5,2) = 10

For each of these, Sergio can choose 10 different numbers

So we have 100 possible ways for Tina to choose 2, and Sergio to choose one number.

We can actually list them

1 2 sum of digits = 3 leaving Sergio to choose 7 larger: prob = 7/100

1 3 sum of digits = 4 leaving Sergio to choose 6 larger: prob = 6/100

1 4 sum of digits = 5 leaving Sergio to choose 5 larger: prob = 5/100

1 5 sum of digits = 6 leaving Sergio to choose 4 larger: prob = 4/100

2 3 sum of digits = 5 leaving Sergio to choose 5 larger: prob = 5/100

2 4 sum of digits = 6 leaving Sergio to choose 4 larger: prob = 4/100

2 5 sum of digits = 7 leaving Sergio to choose 3 larger: prob = 3/100

3 4 sum of digits = 7 leaving Sergio to choose 3 larger: prob = 3/100

3 5 sum of digits = 8 leaving Sergio to choose 2 larger: prob = 2/100

4 5 sum of digits = 9 leaving Sergio to choose 1 larger: prob = 1/100

sum of those probs = 40/100 = 2/5

check my logic on this one.

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