Posted by Anonymous on Thursday, November 24, 2011 at 8:22am.
As+Ls=2100
Ls=large spider as=average sized spider
Ls=20As
so
as+20as=2100
21as=2100
as=100
The average sized spider lays 100 eggs at one time
let the no. of eggs laid by average side spider=x
given, 20x= 2100
divide both sides by 20
20x/20 = 2100/20
x =105
. .
. the no. of eggs laid by an average side spider = 105 eggs
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