Posted by maria on Thursday, November 24, 2011 at 7:54am.
number of ways that the 3 reds and the 2 whites
can be arranged = 5!/(3!2!) = 10
Now place a white at the end, then the number of ways to arrange the remaining 4 is 4!/(2!2!) = 6
so prob that the last one will be white = 6/10 = 3/5
thank you very much. can u help me for other quistion pleasee
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