Posted by **Andrew** on Thursday, November 24, 2011 at 6:55am.

A wire P has resistance R. If the wire is stretched and its length is increased by 10%, what would be the percentage change in its resistance? (Assume the density of the wire remains constant)

A) - 10%

B) 0 %

C) 10%

D) 20%

My thoughts:

Since resistance is R = resistivity x length / cross-sectional area of wire, when the length increases by 10%, R should increase by 10%. Cross sectional area doesn't change as the wire is stretched, as the atoms are horizontally pulled apart in the direction of the stretch and have a wider spacing between each other.

However, the answer given is D.

- College Physics -
**drwls**, Thursday, November 24, 2011 at 2:19pm
Since the density stays the same, the volume (area*length) must stay the same and the cross sectional area must decrease.

Resistance = Resisitivity*Length/Area

(new resistance)/(old resistance)

= [(new length)/(old length)]*(old area)/(new area)]

= 1.1/(1/1.1) = 1.21

The increase is acually 21%, not 20%

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