Posted by Andrew on Thursday, November 24, 2011 at 6:55am.
A wire P has resistance R. If the wire is stretched and its length is increased by 10%, what would be the percentage change in its resistance? (Assume the density of the wire remains constant)
A)  10%
B) 0 %
C) 10%
D) 20%
My thoughts:
Since resistance is R = resistivity x length / crosssectional area of wire, when the length increases by 10%, R should increase by 10%. Cross sectional area doesn't change as the wire is stretched, as the atoms are horizontally pulled apart in the direction of the stretch and have a wider spacing between each other.
However, the answer given is D.

College Physics  drwls, Thursday, November 24, 2011 at 2:19pm
Since the density stays the same, the volume (area*length) must stay the same and the cross sectional area must decrease.
Resistance = Resisitivity*Length/Area
(new resistance)/(old resistance)
= [(new length)/(old length)]*(old area)/(new area)]
= 1.1/(1/1.1) = 1.21
The increase is acually 21%, not 20%
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