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March 29, 2017

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I'm having a hard time answering this question. I don't know what equation to use? I've tried using dy= Viyt + 1/2 gt^2. Water is leaving a hose at 6.8 m/s. If the target is 2 m away horizontally, What angle should the water have initially? thank you :D

  • physics - ,

    Range = (Vo^2/g)*sin(2A) = 2.0 m
    Vo = 6.8 m/s is the initial velocity.
    Solve for A.
    sin(2A) = 0.4239
    2A = 25.08 or 154.92 degrees
    A = 12.54 or 77.46 degrees

  • physics - ,

    Thank YOU :D

  • physics - ,

    Aunt "Maddy Shane" was the nickname given to my grandmother by her nieces. Shane was the maiden name.
    I never thought I'd see that name again.

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