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December 22, 2014

December 22, 2014

Posted by **Watermelon** on Thursday, November 24, 2011 at 3:48am.

- AP calculus -
**Steve**, Thursday, November 24, 2011 at 5:44ama+5d = 23

6/2 * [a + (a+5d)] = 78

a + 5d = 23

6a + 15d = 78

a=3

d=4

sequence: 3 7 11 15 19 23

sum: 78

- AP calculus -
**Watermelon**, Thursday, November 24, 2011 at 7:03amGiven an arithmetic progression -7,-3,1,..., state three consecutive terms in this progression which sum up to 75.

- AP calculus -
**Steve**, Thursday, November 24, 2011 at 7:03pmThe kth term is a+(k-1)d

so you want

3a + (k-1 + k + k+1)d = 75

3(-7) + 3k(4) = 75

12k = 96

k=8

So, the 8th,9th,10th terms are

21,25,29 add up to 75

- AP calculus -
**NCaxUXvPLp**, Monday, December 12, 2011 at 4:34amI can already tell that's gonna be super hlepufl.

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