(.050 minus 2pie over the square root of 6.18 divided by 2pie over the square root of 6.18)times 100
I think the answer is 5 because everything cancels out except .050*100 right?
{[0.05 - (6.28/sqrt6.18)]*(sqrt6.18/6.28}*100
=[0.05 -1]*100 = -95
I don't see how the 0.05 cancels
Find the LCM of 6x square root of 2 +30x and 3x over the square root2 + 18x +15
To solve the expression (.050 - 2π/√6.18) / (2π/√6.18) * 100, we need to follow the order of operations (also known as PEMDAS).
1. First, we simplify what's inside the parentheses: (.050 - 2π/√6.18) / (2π/√6.18)
2. Next, we perform the division inside the parentheses: (.050 - 2π/√6.18) divided by (2π/√6.18)
3. To divide by a fraction, we multiply by its reciprocal: (.050 - 2π/√6.18) * (√6.18/2π)
4. Now we can simplify further: (.050 * √6.18 - 2π * √6.18) / (2π * 2√6.18)
5. Since both terms in the numerator have a common factor of √6.18, we can factor it out: √6.18 * (.050 - 2π) / (2π * 2√6.18)
6. The √6.18 in the numerator cancels out with the 2√6.18 in the denominator: (.050 - 2π) / (2π * 2)
7. Finally, we can simplify the expression: (.050 - 2π) / (4π)
Therefore, the final answer is (.050 - 2π) / (4π).