Write the molecular equation, the complete ionic equation, and the net ionic equation for the reaction of barium hydroxide with sodium nitrate.

There is no reaction between these. If you want the ionic equation, simply separate each into the respective ions and show them (I suppose these are water solution) as aqueous.

To write the molecular equation, complete ionic equation, and net ionic equation for the reaction of barium hydroxide with sodium nitrate, we need to follow a series of steps:

Step 1: Write the balanced chemical equation.
The balanced chemical equation for the reaction between barium hydroxide (Ba(OH)2) and sodium nitrate (NaNO3) can be determined by swapping the cations and anions to form the products. The balanced equation is:

Ba(OH)2 + 2NaNO3 → Ba(NO3)2 + 2NaOH

Step 2: Write the complete ionic equation.
In the complete ionic equation, all soluble ionic compounds dissociate into their respective ions. The complete ionic equation for the reaction is:

Ba^2+(aq) + 2OH^-(aq) + 2Na^+(aq) + 2NO3^-(aq) → Ba^2+(aq) + 2NO3^-(aq) + 2Na^+(aq) + 2OH^-(aq)

Step 3: Write the net ionic equation.
The net ionic equation focuses only on the ions and molecules that actively participate in the reaction. In this case, the spectator ions (ions present on both sides of the equation which do not undergo any changes) are the Ba^2+ and NO3^- ions. Canceling out the spectator ions, we get the net ionic equation:

2OH^-(aq) + 2Na^+(aq) → 2NaOH(aq)

Therefore, the molecular equation is: Ba(OH)2 + 2NaNO3 → Ba(NO3)2 + 2NaOH
The complete ionic equation is: Ba^2+(aq) + 2OH^-(aq) + 2Na^+(aq) + 2NO3^-(aq) → Ba^2+(aq) + 2NO3^-(aq) + 2Na^+(aq) + 2OH^-(aq)
And the net ionic equation is: 2OH^-(aq) + 2Na^+(aq) → 2NaOH(aq)