What is the mass, in grams, of NaCl formed from the reaction of 2.75 mL of a 6.00 M Na2SO4 solution and 8.30 mL of 2.5 M solution of HCl?

I have news for you. There is no reaction between Na2SO4 and HCl.

What is the mass, in grams, of NaCl formed from the reaction of 2.75 mL of a 6.00 M Na2SO4 solution and 8.30 mL of 2.5 M solution of HCl?

To determine the mass of NaCl formed from the reaction of Na2SO4 and HCl, we need to follow these steps:

Step 1: Write and balance the chemical equation
The balanced chemical equation for the reaction between Na2SO4 and HCl is:

Na2SO4 + 2HCl → 2NaCl + H2SO4

Step 2: Calculate the number of moles of each reactant
Use the formula:

moles = concentration (M) × volume (L)

For Na2SO4:
moles of Na2SO4 = concentration of Na2SO4 (M) × volume of Na2SO4 (L)
= 6.00 M × 0.00275 L
= 0.0165 moles

For HCl:
moles of HCl = concentration of HCl (M) × volume of HCl (L)
= 2.5 M × 0.0083 L
= 0.02075 moles

Step 3: Determine the limiting reactant
To find the limiting reactant, compare the moles of each reactant using the stoichiometry of the balanced equation. The stoichiometric ratio tells us that 1 mole of Na2SO4 reacts with 2 moles of HCl to form 2 moles of NaCl.

Based on this stoichiometric ratio:
- Na2SO4 has 0.0165 moles
- HCl has 0.02075 moles

Since Na2SO4 has fewer moles than HCl, it is the limiting reactant.

Step 4: Calculate the moles of NaCl formed
Using the stoichiometry of the balanced equation, we know that 1 mole of Na2SO4 reacts to form 2 moles of NaCl. Therefore, the moles of NaCl formed can be calculated as:

moles of NaCl = (moles of Na2SO4) × 2
= 0.0165 moles × 2
= 0.033 moles

Step 5: Convert moles to grams
We can now use the molar mass of NaCl to convert moles to grams. The molar mass of NaCl is approximately 58.44 g/mol.

mass of NaCl = (moles of NaCl) × (molar mass of NaCl)
= 0.033 moles × 58.44 g/mol
= 1.93052 grams

Therefore, the mass of NaCl formed from the reaction is approximately 1.93052 grams.