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January 29, 2015

January 29, 2015

Posted by **ms** on Wednesday, November 23, 2011 at 8:41pm.

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**Writeacher**, Wednesday, November 23, 2011 at 9:09pmIf you really want an expert to help you, be sure to follow directions and type your

__subject__in the**School Subject**box. Any other words,__including obscure abbreviations__, are likely to delay responses from a teacher who knows that subject well.

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**Steve**, Thursday, November 24, 2011 at 5:03amoj in x liters of 30% = .3x

oj in (20-x) liters of 10% = .1(20-x)

oj in 20 liters of 18% = .18(20)

.3x + .1(20-x) = .18(20)

.3x + 2 - .1x = 3.6

.2x = 1.6

x = 8

so, 8L of 30% + 12L of 10% = 20L of 18%

8*.3 + 12*.1 = 2.4+1.2 = 3.6 = .18*20

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