Posted by Kay on Wednesday, November 23, 2011 at 5:34pm.
A rectangular storage container with a lid is to have a volume of 8 m. The length of its base is twice the width. Material for the base costs $4 per m. Material for the sides and lid costs $8 per m. Find the dimensions of the container which will minimize cost and the minimum cost.
base width = m
base length = m
height = m

HELP!! OPTIMIZATION CALCULUS  bobpursley, Wednesday, November 23, 2011 at 5:45pm
This is pretty easy.
area sides=2L*m+2Wm
area bottom= LW
area lid= LW
Volume=lwm
But l=2w
volume=2w^2 m
or m= 4/w^2
costfunction= 4*basearea+8(toparea+sides)
Now, write that cost function in terms of w (substitute)
take the derivatative. with respect to w, set to zero,and solve for w, then use your relations to get l, and h.

HELP!! OPTIMIZATION CALCULUS  Kay, Wednesday, November 23, 2011 at 8:47pm
i get a derivcative of 24w^2+24w^1
is that correct?
Answer This Question
Related Questions
 Calculus optimization  A rectangular storage container with a lid is to have a ...
 Calculus  A rectangular storage container with an open top is to have a volume ...
 Calculus  A rectangular storage container with an open top is to have a volume ...
 Calc 1 (Optomization)  A rectangular storage container with an open top is to ...
 Calc 1  A rectangular storage container with an open top is to have a volume of...
 Calculus  AM having problems understanding what equations to use for this word ...
 Calc  A rectangular storage container with an open top is to have a volume of ...
 math (calc)  At noon, ship A is 150 km west of ship B. Ship A is sailing east ...
 Calculus  A rectangular box is to have a square base and a volume of 20 ft3. ...
 calculus  A rectangular box is to have a square base and a volume of 50 ft3. ...
More Related Questions