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December 19, 2014

December 19, 2014

Posted by **Emil** on Wednesday, November 23, 2011 at 2:09pm.

A: 4,-2

B:-2,-1

C: 4,3

How do i get the height of it in relation BC?

And, how do i calculate the total area of the triangle?

Made this atm:

AB:

((-2)-4)/((-1)-2) = 2;

y-2=2(x-1)

y = 2*x;

BC:

(4+2)/(3+1) = 3/2;

y-2 = 3/2*(x-1);

y = (3/2)*x+1/2;

Took explanation out, it is in another language ;)

- math -
**Reiny**, Wednesday, November 23, 2011 at 4:33pmIf you were finding slope, then you have it upside down.

slope AB = (-2 + 1)/(4+2) = -1/6

slope of BC = (3+1)/(4+2) = 4/6 = 2/3

equation of BC

y-3 = (2/3)(x-4)

3y - 9 = 2x - 8

2x - 3y + 1 = 0

distance from A(4,-2) to BC

= |2(4) - 3(-2) + 1|√(2^2 + (-3)^2)

= 15/√13

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