Posted by Anonymous on Tuesday, November 22, 2011 at 10:37pm.
Suppose the simple pendulum shown below were released from an angle of θ = 74°, with L = 0.73 m and m = 0.25 kg..What angle of release would give half the speed of that for the 74° release angle at the bottom of the swing?

physics  Anonymous, Tuesday, November 22, 2011 at 10:48pm
Suppose the simple pendulum shown below were released from an angle of θ = 74°, with L = 0.73 m and m = 0.25 kg..What angle of release would give half the speed of that for the 74° release angle at the bottom of the swing?

physics  Fizzylicous, Tuesday, November 22, 2011 at 10:50pm
You must have been given a formula to calculate this problem. What formulas do you have? You can't just expect to receive an answer without you asking what you need help on and jotting down the formulas, that's being pure lazy.

physics  drwls, Wednesday, November 23, 2011 at 7:25am
For half the speed at the bottom, you would need 1/4 the initial potential energy.
The initial P.E. is proportional to
(1  cos A)
where A is the initial angle from vertical.
1  cos74 = 0.7244
For 1/4 of that value,
1  cosA = 0.1811
cosA = 0.8189
A = 35.0 degrees
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