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November 22, 2014

November 22, 2014

Posted by **Robert** on Tuesday, November 22, 2011 at 10:35pm.

If a 1.23 m long wire will vibrate 325 times each second when the tension is 115 N, determine the number of vibrations per second if the wire is shortened to 0.95 m and the tension is decreased to 92.0 N.

- Mathematic -
**Reiny**, Wednesday, November 23, 2011 at 12:48amfrequency = k √t/L

given: 325 = k√115/1.23

k = 1.23(325)/√115

for 2nd case

frequency = (1.23(325)/√115) √92/.95

= .....

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