Posted by **parth** on Tuesday, November 22, 2011 at 9:03pm.

brand 1 beer contain 8% alcohol and brand2 contain 6.5% of alcohol. how many litres of each alcohol must be added to produce 600 l of a new brand containing 7 % alcohol?

- maths -
**Steve**, Wednesday, November 23, 2011 at 12:08am
Concentrate on the amount of alcohol. No matter how much water is sloshed around in various concentrations, the amount of alcohol is what you want to keep track of.

You have n liters of 6.5% beer, and thus 600-n liters of 8% beer

Alcohol in n liters of 6.5% = .065n

Alcohol in 600-n liters of 8% = .08(600-n)

At the end, you have 600 liters of 7% beer, holding 600*.07 alcohol.

Add things up:

.065n + .08(600-n) = .07*600

.065n + 48 - .08n = 42

.015n = 6

n = 400

So, mix 400 liters of 6.5% beer with 200 liters of 8% beer

Note that 7% is 1/3 of the way between 6.5% and 8%. Thus, you need twice as much 6.5% beer as 8% beer.

## Answer this Question

## Related Questions

- Maths - How much pure alcohol has to be added to 400ml of a solution containing ...
- algebra - moonshine has 50 liters of a 70% alcohol solution.how many liters of ...
- Math - - A)For a certain commodity the demand equation is given by D=-3p+20. At...
- algebra - How many kilograms of pure alcohol must be added to 40 kg of a 70% ...
- Math - 1. In the lab, Deon has two solutions that contain alcohol and is mixing ...
- math - in the lab, tom has two solutions that contain alcohol and is mixing them...
- math - how many oz of 25% alcohol solution must be mixed with 14oz of 30oz ...
- math - A solution of alcohol and water is a% alcohol where a = 40. The solution ...
- Math please - A 75% alcohol concentration mixture of water and alcohol was made ...
- pharmacy math who helps me step by step for me - How much 30% alcohol, 45% ...

More Related Questions