Posted by luna on Tuesday, November 22, 2011 at 2:59pm.
This is an example of why we always get everything on the left side, then factor to make the product zero:
(x+4)(x-12) = 5x
x^2 - 8x - 48 = 5x
x^2 - 13x - 48 = 0
(x-16)(x+3) = 0
Now we have a zero product. That means that if any of the factors is zero, then the product is also zero.
So, x = -3 or 16
Now do the same steps with the second equation
Related Questions
Algebra - (x)/(x-3)-4-(2x-5)/(x+2) I posted something before this, so now this ...
Algebra - (x)/(x-3)-4-(2x-5)/(x+2) I posted something before this, so now this ...
math/algebra - solve each of the following systems by substitution. 16) 5x -2y...
Math - Can someone please check my answers below for accurateness? The ...
Algebra - The answer in the book however says -(5x^2-17x-9)/(x-3)(x+2) so I don...
Algebra - x/(x-3)-4-(2x-5)/(x+2) If the problem is this: x/(x - 3) - 4 - (3x - 5...
math,help,algebra I - I need help can someone help me get unstuck and let me ...
08.02 Multiplying and Dividing Rational Expression - Can someone solve these for...
college algebra - how do I solve this: (17x^3-5x^2+4x-3)-(5x^3-9x^2-8x+11) and ...
Math 8R: Homework Check - Part 2 - Part 2: Simplify by combining like terms and...
For Further Reading